3.2801 \(\int (c x)^{-1-4 n-n p} (a+b x^n)^p \, dx\)

Optimal. Leaf size=179 \[ \frac {6 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+4}}{a^4 c n (p+1) (p+2) (p+3) (p+4)}-\frac {6 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+3}}{a^3 c n (p+1) (p+2) (p+3)}+\frac {3 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+2}}{a^2 c n (p+1) (p+2)}-\frac {(c x)^{-n (p+4)} \left (a+b x^n\right )^{p+1}}{a c n (p+1)} \]

[Out]

-(a+b*x^n)^(1+p)/a/c/n/(1+p)/((c*x)^(n*(4+p)))+3*(a+b*x^n)^(2+p)/a^2/c/n/(1+p)/(2+p)/((c*x)^(n*(4+p)))-6*(a+b*
x^n)^(3+p)/a^3/c/n/(1+p)/(2+p)/(3+p)/((c*x)^(n*(4+p)))+6*(a+b*x^n)^(4+p)/a^4/c/n/(p^2+3*p+2)/(p^2+7*p+12)/((c*
x)^(n*(4+p)))

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Rubi [A]  time = 0.13, antiderivative size = 179, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {273, 264} \[ \frac {3 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+2}}{a^2 c n (p+1) (p+2)}-\frac {6 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+3}}{a^3 c n (p+1) (p+2) (p+3)}+\frac {6 (c x)^{-n (p+4)} \left (a+b x^n\right )^{p+4}}{a^4 c n (p+1) (p+2) (p+3) (p+4)}-\frac {(c x)^{-n (p+4)} \left (a+b x^n\right )^{p+1}}{a c n (p+1)} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^(-1 - 4*n - n*p)*(a + b*x^n)^p,x]

[Out]

-((a + b*x^n)^(1 + p)/(a*c*n*(1 + p)*(c*x)^(n*(4 + p)))) + (3*(a + b*x^n)^(2 + p))/(a^2*c*n*(1 + p)*(2 + p)*(c
*x)^(n*(4 + p))) - (6*(a + b*x^n)^(3 + p))/(a^3*c*n*(1 + p)*(2 + p)*(3 + p)*(c*x)^(n*(4 + p))) + (6*(a + b*x^n
)^(4 + p))/(a^4*c*n*(1 + p)*(2 + p)*(3 + p)*(4 + p)*(c*x)^(n*(4 + p)))

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 273

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(
a*c*n*(p + 1)), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; FreeQ[
{a, b, c, m, n, p}, x] && ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[p, -1]

Rubi steps

\begin {align*} \int (c x)^{-1-4 n-n p} \left (a+b x^n\right )^p \, dx &=-\frac {(c x)^{-n (4+p)} \left (a+b x^n\right )^{1+p}}{a c n (1+p)}-\frac {3 \int (c x)^{-1-4 n-n p} \left (a+b x^n\right )^{1+p} \, dx}{a (1+p)}\\ &=-\frac {(c x)^{-n (4+p)} \left (a+b x^n\right )^{1+p}}{a c n (1+p)}+\frac {3 (c x)^{-n (4+p)} \left (a+b x^n\right )^{2+p}}{a^2 c n (1+p) (2+p)}+\frac {6 \int (c x)^{-1-4 n-n p} \left (a+b x^n\right )^{2+p} \, dx}{a^2 (1+p) (2+p)}\\ &=-\frac {(c x)^{-n (4+p)} \left (a+b x^n\right )^{1+p}}{a c n (1+p)}+\frac {3 (c x)^{-n (4+p)} \left (a+b x^n\right )^{2+p}}{a^2 c n (1+p) (2+p)}-\frac {6 (c x)^{-n (4+p)} \left (a+b x^n\right )^{3+p}}{a^3 c n (1+p) (2+p) (3+p)}-\frac {6 \int (c x)^{-1-4 n-n p} \left (a+b x^n\right )^{3+p} \, dx}{a^3 (1+p) (2+p) (3+p)}\\ &=-\frac {(c x)^{-n (4+p)} \left (a+b x^n\right )^{1+p}}{a c n (1+p)}+\frac {3 (c x)^{-n (4+p)} \left (a+b x^n\right )^{2+p}}{a^2 c n (1+p) (2+p)}-\frac {6 (c x)^{-n (4+p)} \left (a+b x^n\right )^{3+p}}{a^3 c n (1+p) (2+p) (3+p)}+\frac {6 (c x)^{-n (4+p)} \left (a+b x^n\right )^{4+p}}{a^4 c n (1+p) (2+p) (3+p) (4+p)}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 69, normalized size = 0.39 \[ -\frac {x (c x)^{-n (p+4)-1} \left (a+b x^n\right )^p \left (\frac {b x^n}{a}+1\right )^{-p} \, _2F_1\left (-p-4,-p;-p-3;-\frac {b x^n}{a}\right )}{n (p+4)} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^(-1 - 4*n - n*p)*(a + b*x^n)^p,x]

[Out]

-((x*(c*x)^(-1 - n*(4 + p))*(a + b*x^n)^p*Hypergeometric2F1[-4 - p, -p, -3 - p, -((b*x^n)/a)])/(n*(4 + p)*(1 +
(b*x^n)/a)^p))

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fricas [A]  time = 0.77, size = 294, normalized size = 1.64 \[ -\frac {{\left (6 \, a b^{3} p x x^{3 \, n} e^{\left (-{\left (n p + 4 \, n + 1\right )} \log \relax (c) - {\left (n p + 4 \, n + 1\right )} \log \relax (x)\right )} - 6 \, b^{4} x x^{4 \, n} e^{\left (-{\left (n p + 4 \, n + 1\right )} \log \relax (c) - {\left (n p + 4 \, n + 1\right )} \log \relax (x)\right )} - 3 \, {\left (a^{2} b^{2} p^{2} + a^{2} b^{2} p\right )} x x^{2 \, n} e^{\left (-{\left (n p + 4 \, n + 1\right )} \log \relax (c) - {\left (n p + 4 \, n + 1\right )} \log \relax (x)\right )} + {\left (a^{3} b p^{3} + 3 \, a^{3} b p^{2} + 2 \, a^{3} b p\right )} x x^{n} e^{\left (-{\left (n p + 4 \, n + 1\right )} \log \relax (c) - {\left (n p + 4 \, n + 1\right )} \log \relax (x)\right )} + {\left (a^{4} p^{3} + 6 \, a^{4} p^{2} + 11 \, a^{4} p + 6 \, a^{4}\right )} x e^{\left (-{\left (n p + 4 \, n + 1\right )} \log \relax (c) - {\left (n p + 4 \, n + 1\right )} \log \relax (x)\right )}\right )} {\left (b x^{n} + a\right )}^{p}}{a^{4} n p^{4} + 10 \, a^{4} n p^{3} + 35 \, a^{4} n p^{2} + 50 \, a^{4} n p + 24 \, a^{4} n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(-n*p-4*n-1)*(a+b*x^n)^p,x, algorithm="fricas")

[Out]

-(6*a*b^3*p*x*x^(3*n)*e^(-(n*p + 4*n + 1)*log(c) - (n*p + 4*n + 1)*log(x)) - 6*b^4*x*x^(4*n)*e^(-(n*p + 4*n +
1)*log(c) - (n*p + 4*n + 1)*log(x)) - 3*(a^2*b^2*p^2 + a^2*b^2*p)*x*x^(2*n)*e^(-(n*p + 4*n + 1)*log(c) - (n*p
+ 4*n + 1)*log(x)) + (a^3*b*p^3 + 3*a^3*b*p^2 + 2*a^3*b*p)*x*x^n*e^(-(n*p + 4*n + 1)*log(c) - (n*p + 4*n + 1)*
log(x)) + (a^4*p^3 + 6*a^4*p^2 + 11*a^4*p + 6*a^4)*x*e^(-(n*p + 4*n + 1)*log(c) - (n*p + 4*n + 1)*log(x)))*(b*
x^n + a)^p/(a^4*n*p^4 + 10*a^4*n*p^3 + 35*a^4*n*p^2 + 50*a^4*n*p + 24*a^4*n)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b x^{n} + a\right )}^{p} \left (c x\right )^{-n p - 4 \, n - 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(-n*p-4*n-1)*(a+b*x^n)^p,x, algorithm="giac")

[Out]

integrate((b*x^n + a)^p*(c*x)^(-n*p - 4*n - 1), x)

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maple [F]  time = 0.22, size = 0, normalized size = 0.00 \[ \int \left (c x \right )^{-n p -4 n -1} \left (b \,x^{n}+a \right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^(-n*p-4*n-1)*(b*x^n+a)^p,x)

[Out]

int((c*x)^(-n*p-4*n-1)*(b*x^n+a)^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b x^{n} + a\right )}^{p} \left (c x\right )^{-n p - 4 \, n - 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(-n*p-4*n-1)*(a+b*x^n)^p,x, algorithm="maxima")

[Out]

integrate((b*x^n + a)^p*(c*x)^(-n*p - 4*n - 1), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (a+b\,x^n\right )}^p}{{\left (c\,x\right )}^{4\,n+n\,p+1}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^n)^p/(c*x)^(4*n + n*p + 1),x)

[Out]

int((a + b*x^n)^p/(c*x)^(4*n + n*p + 1), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**(-n*p-4*n-1)*(a+b*x**n)**p,x)

[Out]

Timed out

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